-(0.5x^2)+0.5x-0.125=0

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Solution for -(0.5x^2)+0.5x-0.125=0 equation: 



-(0.5x^2)+0.5x-0.125=0

We add all the numbers together, and all the variables

0.5x-(0.5x^2)-0.125=0

We get rid of parentheses

-0.5x^2+0.5x-0.125=0

a = -0.5; b = 0.5; c = -0.125;
Δ = b2-4ac
Δ = 0.52-4·(-0.5)·(-0.125)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-0.5}{-1}=0.5/1$

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